# AP Statistics Unit 6 Practice Test: Inference for Categorical Data: Proportions

Test 6 for AP Stats.

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 Question 1

### A researcher is conducting quality assurances on a batch of products. To estimate what proportion is defective, the researcher wants to make a one-sample z interval with 99% confidence $(z* = 2.58)$. The margin of error should be no more than 2%. A previous sample suggested 5% of the products are defective. What is the smallest sample size required to fit these parameters?

 A 52 B 790 C 791 D 1024
Question 1 Explanation:
To calculate the smallest sample size for the given parameter, we use $2.58* \sqrt{\dfrac{(0.05(1-0.05)}{n}} ≤ 0.02$

$\sqrt{\dfrac{(0.05(1-0.05)}{n}} ≤ \dfrac{0.02}{2.58}$

$\sqrt{\dfrac{0.0475}{n}} ≤ \dfrac{0.02}{2.58}$

$\dfrac{0.0475}{n} ≤ (\dfrac{0.02}{2.58})2$

$0.0475≤n* (\dfrac{0.02}{2.58})2$

$(\dfrac{0.02}{2.58})2*0.0475≤n$

$790.4475≤n$

The smallest whole number sample size will be 791.
 Question 2

4. ### The width of the confidence interval is twice the margin of error

 A I and II B II and III C I and III D II and IV
Question 2 Explanation:
The width of the confidence interval tends to decrease as the sample size increases, so statement (I) is false. The width of the confidence interval for a population proportion is twice the margin of error, so (III) is false and (IV) is true. The width of the confidence interval increases as the confidence level increases, so (II) is true. D is correct.
 Question 3

### A teacher is trying to improve student mastery using a new teaching method. The current student mastery is 60%. The teacher does a random sample under the new teaching method and observes a new mean student mastery is 75%. What are appropriate hypotheses for the significance test?

 A $H_0:p=0.60; H_a: p=0.75$ B $H_0:p=0.60; H_a: p>0.60$ C $H_0:p>0.60; H_a: p=0.75$ D $H_0:p>0.60; H_a: p=0.60$
Question 3 Explanation:
The null hypothesis should be a statement of equality using the reported mean. The alternate hypothesis is testing for improvement. Answer choice B is correct.
 Question 4

### A student reads a newspaper article that estimates that 60% of students from the local high school attend a four-year college. The student is curious about that number and conducts a separate random sample to survey students. In the random sample of 80 students, 56 reported they were attending a four-year college. Calculate the test statistic for this population proportion.

 A 0.42 B 0.7 C 1.3 D 1.83
Question 4 Explanation:
The test statistic is $\dfrac{sample statistic - null value of parameter}{standard deviation of statistic}$

$56÷80 = 0.7$

$\dfrac{0.7-0.6}{\sqrt{\dfrac{0.6(1-0.6)}{80}}} = \dfrac{0.1}{\sqrt{\dfrac{0.24}{80}}} ≈1.83$

 Question 5

### A medical researcher is testing the null hypothesis that a new treatment is no more effective than a previous treatment for a certain disease. What would be a Type I error in this situation?

 A The researcher concludes the treatment is more effective when it is actually not more effective. B The researcher concludes the treatment is not more effective when it is actually more effective. C The researcher doesn’t conclude the treatment is more effective when it is not more effective. D None of these describe a Type I error.
Question 5 Explanation:
A Type I error is when the null hypothesis is true, but is rejected. In statement A, the null hypothesis (the treatment is no more effective) is true, but the researcher does not come to that conclusion. Statement A is correct.
 Question 6

### Assuming no other factors are changed, changing which factor can reduce the probability of a Type II error?

 A Decrease sample size B Decrease significance level (α) of test C Decrease standard error D Decrease the distance from the true parameter to the null
Question 6 Explanation:
The probability of a Type II error decreases when any of the following occurs:
- Increase sample size
- Increase significance level (α) of test
- Decrease standard error
- True parameter value is farther from null

Statement C is correct.
 Question 7

### The student council wants to use these results to construct a 95% confidence interval (z*=1.96) to estimate the proportion of students in those groups who support the construction project. Assume all conditions for inference have been met. What is a correct 95% confidence interval based on the samples?

 A $(-0.1, 0.1)$ B $(0, 0.1)$ C $(-0.2, 0.2)$ D $(0, 0.2)$
Question 7 Explanation:
The confidence interval can be calculated by
$(0.72-0.70)±1.96 \sqrt{\dfrac{0.72(0.28)}{100}+\dfrac{0.7(0.3)}{120}}$
$≈0.02±0.120≈(-0.1,0.1).$
 Question 8

4. ### $H_0:p_1≤p_2$

 A I and III B I and IV C II and III D II and IV
Question 8 Explanation:
A null hypothesis needs to be a statement of equality, such as $p_1=p_2$ or $p_1-p_2=0$. The alternative hypothesis can’t include the inequality, so (IV) is incorrect. Answer choice A is correct.
 Question 9

### Which of the following is true about checking for independence when testing a difference between population proportions?

 A $n≤10%N$ for at least one sample B $n≤10%N$ for both samples C $n≥10%N$ for at least one sample D $n≥10%N$ for both samples
Question 9 Explanation:
When checking for independence, data should be collected using two independent random samples or a randomized experiment, and $n_1≤10%N_1$ and $n_2≤10%N_2$. Answer B is correct.
 Question 10

### A principal wants to gather evidence for a mandated tutoring program. To do this, a random sample of students is taken from those in the voluntary tutoring program, and those not in the tutoring program. In the voluntary tutoring program, 75% of students are passing all of their classes. For those not in the program, 65% are passing all classes. The principal performs a significance test on the difference of proportions and the p-value returned is 0.05. What conclusion should be drawn for a 95% level of confidence?

 A The p-value does not indicate a statistically significant difference in population proportions, so we should accept the null hypothesis. B The p-value does not indicate a statistically significant difference in population proportions, so we should reject the null hypothesis. C The p-value indicates a statistically significant difference in the population proportions, so we should accept the null hypothesis. D The p-value indicates a statistically significant difference in the population proportions, so we should reject the null hypothesis.
Question 10 Explanation:
A p-value of $0.05$ is $≤ 1-0.95$, which is enough to indicate a statistically significant difference in the population proportions. This means that we reject the null hypothesis (that the population proportions are equal). Statement D is correct.
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