**Difficulty Level – 4: Difficult**

*Directions: **Solve each problem and then click on the correct answer. You are permitted to use a calculator on this test.*

Congratulations - you have completed .
You scored %%SCORE%% out of %%TOTAL%%.
Your performance has been rated as %%RATING%%

Your answers are highlighted below.

Question 1 |

### In a competition where the highest score wins, the scores of the top four competitors are consecutive even integers whose sum is 36. What is the score of the competitor who finished in second place?

$6$ | |

$8$ | |

$10$ | |

$12$ | |

$14$ |

Question 1 Explanation:

The correct answer is (C). Use an equation to represent the situation:

$x + x + 2 + x + 4 + x + 6 = 36$

Solve for $x$ to find 6, but recognize that this is the least of the four scores. The score of the competitor who finished in second place will be:

$x + 4 = 6 + 4 = 10$

$x + x + 2 + x + 4 + x + 6 = 36$

Solve for $x$ to find 6, but recognize that this is the least of the four scores. The score of the competitor who finished in second place will be:

$x + 4 = 6 + 4 = 10$

Question 2 |

### A company will be using a pie chart to represent the total expenditures of its various departments. If the breakdown of its expenditures is as follows: 19% Research and Development, 33% Marketing, 22% Payroll. If the remaining expenditures represent $12,250, what is the dollar amount spent on Research and Development (Round to nearest unit)?

$7750$ | |

$7927$ | |

$8331$ | |

$8952$ | |

$9113$ |

Question 2 Explanation:

The correct answer is (D). Because they will use a pie chart, we know the percentages spent on each department will add up to 100%, meaning the remaining expenditures represent 26% of all expenditures. We can set up a proportion between the 19% spent on R&D and the 26% spent on others:

$\dfrac{19}{26} = \dfrac {x}{12{,}250}$

Cross multiply to solve for $x$ to find 8951.9 which rounds to 8952.

$\dfrac{19}{26} = \dfrac {x}{12{,}250}$

Cross multiply to solve for $x$ to find 8951.9 which rounds to 8952.

Question 3 |

### The vertices of square *ABCD* have coordinates (0,0), (-8,0), (-8,8), and (0,8) in the standard (*x*, *y*) coordinate plane, and circle *O* is inscribed in square *ABCD*. Which of the following equations represents circle *O*?

$(x+4)^2+(y+4)^2=4$ | |

$(x −4)^2+(y −4)^2=16$ | |

$(x+4)^2+(y −4)^2=16$ | |

$(x+4)^2+(y-4)^2=4$ | |

$(x −4)^2+(y+4)^2=8$ |

Question 3 Explanation:

The correct answer is (C). The equation of a circle is given in the form (

The center of circle

*x*−*a*)^{2}+ (*y*−*b*)^{2}=*r*^{2}, where*a*is the x-coordinate of the center point,*b*is the y-coordinate of the center point, and*r*is the radius. Since square*ABCD*has sides of length 8, we know that circle*O*must have a radius of 4 units. Therefore, the equation of circle*O*should end in the term 4^{2}or 16. We can eliminate answers (A), (D), and (E), because they do not meet this condition.The center of circle

*O*has an x-coordinate of −4, so we would expect circle*O*'s equation to contain the term (*x*− (−4))^{2}, or (*x*+ 4)^{2}. This eliminates answer (B) from consideration, leaving us with answer (C) as the correct answer. Since circle*O*has center (−4, 4) and radius 4, its full equation should read (*x*+ 4)^{2}+ (*y*− 4)^{2}= 16.Question 4 |

### The average of 7 numbers is 24. The smallest of the numbers is 2 and the largest of the numbers is 31. What is the average of the middle 5 numbers?

$25$ | |

$27$ | |

$30$ | |

$31$ | |

$32$ |

Question 4 Explanation:

The correct answer is (B). Begin by setting up an equation representing the average:

$(2 + x + 31) ÷ 7 = 24$

Solve for $x$ to find 135 and recognize that this $x$ represents the sum of the remaining 5 scores. To find the average, divide 135 by 5 to find 27.

$(2 + x + 31) ÷ 7 = 24$

Solve for $x$ to find 135 and recognize that this $x$ represents the sum of the remaining 5 scores. To find the average, divide 135 by 5 to find 27.

Question 5 |

### Two side lengths of a triangle are 5 and 6, which of the following CANNOT be the length of the third side?

$2$ | |

$3$ | |

$5$ | |

$10$ | |

$12$ |

Question 5 Explanation:

The correct answer is (E). If a triangle has side lengths $a$, $b$, and $c$, the sum of the lengths of any 2 sides must be larger than the length of the 3rd side. So in this case 5 + 6 = 11 must be larger than side length $c$. From the answer choices, 12 is the only length greater than 11, so it cannot be the length of the third side.

Question 6 |

### Danny wishes to shift the graph of the function $f(x) = x^2$ four places to the right and six places down from the origin $(0, 0)$. Which equation represents this translation?

$f(x) = (x − 6)^2 − 6$ | |

$f(x) = x − 4^2 + 6$ | |

$f(x) = x + 4^2 − 6$ | |

$f(x) = (x^2 − 4)^2 − 6$ | |

$fƒ(x) = (x − 4)^2 − 6$ |

Question 6 Explanation:

The correct answer is (E). The vertex form of a parabola is:

$a(x − h)^2 + k$, where $(h, k)$ represents the vertex.

We wish to translate our vertex from $(0, 0)$ to $(4, −6)$ so $h = 4$ and $k = −6$.

$f(x) = (x − 4)^2 − 6$

$a(x − h)^2 + k$, where $(h, k)$ represents the vertex.

We wish to translate our vertex from $(0, 0)$ to $(4, −6)$ so $h = 4$ and $k = −6$.

$f(x) = (x − 4)^2 − 6$

Question 7 |

### The following input and output values represent a linear relationship. What number does the variable *j* represent?

$2$ | |

$3$ | |

$4$ | |

$5$ | |

$6$ |

Question 7 Explanation:

The correct answer is (B). If the numbers represent a functional relationship, then the slope of the line formed by each 2 points will be the same:

$\dfrac{j−5}{4−0}=\dfrac{2-j}{6-4}$

$\dfrac{j-5}{4}=\dfrac{2-j}{2}$

Cross multiply and solve for $j$:

$2j − 10 = 8 − 4j$

$6j = 18$

$j = 3$

$\dfrac{j−5}{4−0}=\dfrac{2-j}{6-4}$

$\dfrac{j-5}{4}=\dfrac{2-j}{2}$

Cross multiply and solve for $j$:

$2j − 10 = 8 − 4j$

$6j = 18$

$j = 3$

Question 8 |

### What is the matrix product of:

### $ \begin{bmatrix} x & 2x \\ 2x & x \\ \end{bmatrix} $ and $\, \begin{bmatrix} 1 & 1 \\ 1 & 1 \\ 1 & 1 \\ \end{bmatrix} $

$
\begin{bmatrix}
x & 2x \\
2x & x \\
\end{bmatrix}
$ | |

$
\begin{bmatrix}
x+1 & 2x+1 \\
2x+1 & x+1 \\
\end{bmatrix}
$ | |

$
\begin{bmatrix}
2x & x \\
x & 2x \\
\end{bmatrix}
$ | |

$
\begin{bmatrix}
x & 2x \\
2x & x \\
x & 2x \\
\end{bmatrix}
$ | |

$\text{Cannot}$ $\text{be}$ $\text{determined.}$ |

Question 8 Explanation:

The correct answer is (E). Here we are given a 2x2 matrix on the left, and a 3x2 matrix on the right. You may recall that in order to find the product of two matrices, the number of columns in the first matrix must equal the number of rows in the second matrix. For example, a 3x1 matrix multiplied with a 1x3 matrix results in a 3x3 matrix. If the number of columns in the first matrix doesn’t match the number of rows in the second column, in this question for example, we are unable to find the product of the matrices. Consequently, answer choice (E) is correct.

Question 9 |

### Given that $\log_x a = 2$ and $\log_x b = 3$, what is the value of $\log_x(ab)^3$?

$6$ | |

$15$ | |

$36$ | |

$54$ | |

$216$ |

Question 9 Explanation:

The correct answer is (B). The term we are interested in, $\log_x (ab)^3$, is equivalent to $3\log_x (ab)$.

This can also be expressed as 3log

log

= 3log

= 3(2) + 3(3)

= 15 (Choice B).

If you don't know these logarithmic identities, you can still solve the problem by finding values for

log

= log(10)(100 * 1,000)

= log(10)(1,000,000,000,000,000)

= log(10)(10

= 15

This can also be expressed as 3log

_{x}*a*+ 3log_{x}*b*, and since we know the values of log_{x}a and log_{x}*b*, we can substitute to find the answer:log

_{x}(*ab*)^{3}= 3log

_{x}*a*+ 3log_{x}*b*= 3(2) + 3(3)

= 15 (Choice B).

If you don't know these logarithmic identities, you can still solve the problem by finding values for

*x*,*a*, and*b*that satisfy the conditions. Then, simply calculate the value of log(x)(ab)^{3}. The easiest way to do this is to work with a base of 10, which would mean that*x*= 10,*a*= 100, and*b*= 1,000. We can then calculate the answer:log

_{x}(ab)^{3}= log(10)(100 * 1,000)

^{3}= log(10)(1,000,000,000,000,000)

= log(10)(10

^{15})= 15

Question 10 |

### There is to be a walkway built around a circular pond. The walkway will include a curved section extending most of the way around the pond and two straight sections, each measuring 15 feet, extending from the edges that meet in the center at a 90 degree angle to each other, as shown in the figure above. Which of the following is closest to the total length of the walkway, in feet?

$30$ | |

$65$ | |

$71$ | |

$101$ | |

$131$ |

Question 10 Explanation:

The correct answer is (D). The curved section extends all the way around the edge of the pond except the part subtended by the 90-degree angle; therefore, its length is ¾ of the perimeter of the circle, or (¾) (2*

(¾)(30

22.5

Each of the straight segments has length equal to the radius of the pond, or 15 feet, so the total length is around 67.5 + 15 + 15 = 97.5. The actual length will be a little greater than 97.5. The closest answer choice is (D) 101.

*π**r). The radius is 15.(¾)(30

*π*)22.5

*π*= length of the curved portion of the walkway. Pi is about 3, so we can estimate this as 67.5.Each of the straight segments has length equal to the radius of the pond, or 15 feet, so the total length is around 67.5 + 15 + 15 = 97.5. The actual length will be a little greater than 97.5. The closest answer choice is (D) 101.

Once you are finished, click the button below. Any items you have not completed will be marked incorrect.

There are 10 questions to complete.

List |

**Next Practice Test:
ACT Math Practice Test 8 >>
**

**More Practice Tests:**

ACT Math – Main Menu >>

ACT Science Practice >>

ACT English Practice >>

ACT Reading Practice >>